maandag 29 april 2019
Opgave 1
\(
\begin{array}{l}
\left\{ \begin{array}{l}
a + b = 2ab \\
b + c = 3bc \\
a + c = 7ac \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
\frac{1}{c} + \frac{1}{b} = 3 \\
\frac{1}{c} + \frac{1}{a} = 7 \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
\frac{1}{c} - \frac{1}{a} = 1 \\
\frac{1}{c} + \frac{1}{a} = 7 \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
\frac{1}{c} - \frac{1}{a} = 1 \\
\frac{2}{c} = 8 \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
\frac{1}{c} - \frac{1}{a} = 1 \\
c = \frac{1}{4} \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
4 - \frac{1}{a} = 1 \\
c = \frac{1}{4} \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + \frac{1}{a} = 2 \\
a = \frac{1}{3} \\
c = \frac{1}{4} \\
\end{array} \right. \\
\left\{ \begin{array}{l}
\frac{1}{b} + 3 = 2 \\
a = \frac{1}{3} \\
c = \frac{1}{4} \\
\end{array} \right. \\
\left\{ \begin{array}{l}
b = - 1 \\
a = \frac{1}{3} \\
c = \frac{1}{4} \\
\end{array} \right. \\
\end{array}
\)