\(
\eqalign{
& \frac{1}
{4}\left( {x + 1} \right)(x + 5) = - \frac{3}
{4} \cr
& \left( {x + 1} \right)(x + 5) = - 3 \cr
& x^2 + 6x + 5 = - 3 \cr
& x^2 + 6x + 8 = 0 \cr
& (x + 2)(x + 4) = 0 \cr
& x = - 2 \vee x = - 4 \cr}
\)
