Breuken

$1\frac{1}{2} \cdot 9\frac{3}{5} = 9\frac{3}{5} + 4\frac{1}{2} + \frac{3}{{10}} = 9\frac{6}{{10}} + 4\frac{5}{{10}} + \frac{3}{{10}} = 13\frac{{14}}{{10}} = 14\frac{4}{{10}} = 14\frac{2}{5}$