Getallen met 6 delers

 $\eqalign{   & 242 = 2 \cdot 11^2  \to \tau \left( {242} \right) = 2 \cdot \left( {2 + 1} \right) = 6  \cr   & 243 = 2^5  \to \tau \left( {243} \right) = 5 + 1 = 6  \cr   & 244 = 2^2  \cdot 61 \to \tau \left( {244} \right) = \left( {2 + 1} \right) \cdot 2 = 6  \cr   & 245 = 5 \cdot 7^2  \to \tau \left( {245} \right) = 2 \cdot \left( {2 + 1} \right) = 6 \cr}$

• Getallen met 6 delers