\(
\eqalign{
& 242 = 2 \cdot 11^2 \to \tau \left( {242} \right) = 2 \cdot \left( {2 + 1} \right) = 6 \cr
& 243 = 2^5 \to \tau \left( {243} \right) = 5 + 1 = 6 \cr
& 244 = 2^2 \cdot 61 \to \tau \left( {244} \right) = \left( {2 + 1} \right) \cdot 2 = 6 \cr
& 245 = 5 \cdot 7^2 \to \tau \left( {245} \right) = 2 \cdot \left( {2 + 1} \right) = 6 \cr}
\)